Equation of the Normal Line?

Calculus Level 2

f(x) = sqrt{x^{2}+3} at the point (-1, 2). -Find the equation of the normal line.

2x - y = 4 -2x - y = -4 -2x + y = 4 2x + y = -4

Lew Sterling Jr by Lew Sterling Jr , 24, USA

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1 solution

Lew Sterling Jr
Oct 7, 2014

Write a solution.Did beforehand that: -f′(−1)=−½ -Slope of the normal line is −1/ f′(−1) = 2 So... the equation of the normal line at the point (−1, 2) would be y - y1 = m (x - x1); y - 2 = 2 (x + 1); y - 2 = 2x + 2; -2x + y = 4

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Solution is correct but answer is wrong

Shishir G. - 6 years, 8 months ago

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Thanks, I have updated the answer to − 2 x + y = 4 -2x+y = 4 .

In future, if you spot any errors with a problem, you can “report” it by selecting the “dot dot dot” menu in the lower right corner. You will get a more timely response that way.

Calvin Lin Staff - 6 years, 8 months ago

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Just noticed the correction; I was all over the place that day and didn't even see that. xD

Lew Sterling Jr - 6 years, 8 months ago

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