A calculus problem by Naren Bhandari

Calculus Level 2

lim ⁡ x → 0 sin ⁡ ( 1 x ) = ? \large \lim_{x\to 0} \sin\left(\frac{1}{x}\right) =\,?

1 1 ∞ \infty 0 0 Limit does not exist

Naren Bhandari by Naren Bhandari , 21, India

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1 solution

Kaushik Chandra
Oct 17, 2017

LHL is -infinity while RHL is infinity. Because LHL isn't equal to RHL so limit doesn't exist.

0 Helpful 0 Interesting 0 Brilliant 0 Confused

You explanations is wrong.

Naren Bhandari - 1 year, 2 months ago

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