Find the volume of the tetrahedron with corners at , , , and
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The tetrahedron in question has a right-triangular base whose area equals 2 1 ⋅ ( 2 ⋅ 3 ) = 3 square units. With a vertical height equal to 5 units, the volume now calculates to V = 3 1 ⋅ B ⋅ h = 3 1 ⋅ 3 ⋅ 5 = 5 cubic units.