An algebra problem by Sudhagar` M

Algebra Level 1

1/3 rd of the contents of a container evaporated on the 1st day. 3/4th of the remaining contents of the container evaporated on the second day.

What part of the contents of the container is left at the end of the second day?

1/3th of the contents of the container is remaining 2/3th of the contents of the container is remaining 2/6th of the contents of the container is remaining 1/6th of the contents of the container is remaining

2 solutions

Sravanth C.
Jan 7, 2015

let 'x' be the total contents in the container.

so, on the first day x * 1/3 got evaporated i.e, x/3.

therefore the amount of the remaining contents is equal to, x - x/3 = 3x/3 - x/3 =2x/3.

similarly, 2x/3 - 2x/3 * 3/4 gives us the remaining contents on the second day,

               which is= 2x/3 - x/2
                                 =4x - 3x/6
                                 =x/6

therefore 1/6 of the total contents in the container is remaining on the second day.

Abdur Rehman Zahid
Nov 21, 2014

If $\frac{1}{3}$ of the contents evaporated on the first day,then $\frac{2}{3}$ of the contents are left.On the second day $\frac{3}{4}$ of the remaining contents evaporated it means that $\frac{2}{3}\times\frac{3}{4}=\frac{1}{2}$ of the remaining contents evaporated.So $\frac{2}{3}-\frac{1}{2}=\boxed{\frac{1}{6}}$ of the contents are left.

An algebra problem by Sudhagar` M

2 solutions

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