Consider a man standing at point 'P' at a distance 'a' units from the wall. This man has to reach at a point 'Q' (which is on the same side of the wall). Distance between 'P' & 'Q' , measured along the wall is 'b' units , while the distance of 'Q' from the wall is 'c' units. The man has to touch the wall before arriving at point 'Q'.
Locate the point on the wall that the man should touch before arriving at 'Q' , so that the distance covered by him is the least ??
Let the distance of the point be 'x' units . FIND 'x'
DETAILS AND ASSUMPTIONS: a = 1 units b = 25 units c = 4 units
assume the man to travel with a constant speed..
note: TRY TO DO IT BY SOME OTHER WAY THAN CALCULUS...
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Without Calculus. Just in one step..
Take mirror image of Q about x axis. Now we know displacement is equal to shortest distance btw 2 points. So connect source and the image of Q. Now apply simmilarity of triangles.
(x/a)=[b/(a+c)]