A Challenge to all
if 1/(a+w)+1/(b+w)+1/(c+w)+1/(d+w)=2/w
where a,b,c ,d are real and w is the non real cube root of unity.
then find the value of
1) (a+b+c+d)=X
2) 1/(a+1)+1/(b+1)+1/(c+1)+1/(d+1)=Y
Express your answer as (X+Y).
and also please post a solution
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