A classical mechanics problem by Abhiram Rao

Classical Mechanics Level 2

Ten coins of each 10 grams are piled up one over the other . Counting from the bottom , the reaction of 6th coin on the 7th coin is ...... Newtons.

Take acceleration due to gravity as 9.8 m/s^2.


The answer is 0.392.

Abhiram Rao by Abhiram Rao , 18, India

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1 solution

Rifath Rahman
Jan 26, 2020

Counting from the bottom the 7 t h 7^{th} coin has 3 3 more coins on top of it. So, the force it will exert on the 6 t h 6^{th} coin is the weight of the 4 4 coins on top it.

The weight is W = m g ⇒ W = ( 4 ∗ 0.01 ) ∗ 9.8 ⇒ W = 0.392 N W=mg \Rightarrow W=(4* 0.01)*9.8 \Rightarrow W=0.392 N

According to Newton's 3 r d 3^{rd} law, the reaction forces are same is magnitude and opposite in direction, hence

R = W ⇒ R = 0.392 N R=W \Rightarrow R=0.392 N

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