A geometry problem by Akshat Sharda

Geometry Level 2

The position vector of a particle is given as r → = ( t 2 − 4 t + 6 ) i ^ + ( t 2 ) j ^ \overrightarrow{r}=(t^2-4t+6)\hat{i}+(t^2)\hat{j} .

Find the time (in seconds ) after which the velocity and acceleration vector becomes perpendicular to each other.


The answer is 1.

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Akshat Sharda by Akshat Sharda , 21, India

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1 solution

Rishabh Jain
Dec 27, 2015

velocity vector=(2t-4)i(cap)+(2t)j(cap) acceleration vector=2(i(cap)+j(cap)) Clearly velocity and acceleration vector becomes perpendicular to each other when their dot product is zero . Therefore t=1 second.

2 Helpful 0 Interesting 0 Brilliant 0 Confused

How did you get the velocity and acc vectors?

Anik Mandal - 5 years, 5 months ago

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