A classical mechanics problem by anurag jha

A body has kinetic energy E at the angle of projection for max range. Its kinetic energy at the highest point of its path is?

zero E E/2

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1 solution

Alan Guo
Nov 27, 2015

Maximum range (if all friction is neglected) occurs at 45 degrees of elevation, therefore vertical and horizontal initial velocities are equal. At the highest point, vertical velocity is 0 but horizontal remains constant. Therefore, if v v was the initial velocity, and u u was the initial horizontal velocity, then: v 2 = 2 h 2 v^2=2h^2

Since E = . 5 m v 2 , . 5 m h 2 = . 5 m v 2 . 5 = . 5 E E = .5mv^2, .5mh^2 = .5mv^2*.5 = .5E

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