A stone is dropped from a height 19.6metre .what is distance covered by the stone in last half second
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We have, u = 0 , g = 9 . 8 , h = 1 9 . 6 .
From the second equation of motion, we have ⟹ 1 9 . 6 = 2 1 × 9 . 8 × t 2 ⟹ t = 2
Clearly, distance covered in the last half seconds = h 2 − h 1 . 5 , which on evaluating, we have 8.575 as the final answer.