Thermodynamics

Classical Mechanics Level 2

A vessel containing helium { considering it to be an ideal } which expands at constant pressure when 15 kJ 15\text{ kJ} of heat is supplied to it. What will be the variation of internal energy ; work done by gas respectively ___________ \text{\_\_\_\_\_\_\_\_\_\_\_}

3 k J 3kJ ; 2 k J 2kJ 9 k J 9kJ ; 6 k J 6kJ NONE OF THESE 19 k J 19kJ ; 2 k J 2kJ

Jaswinder Singh by Jaswinder Singh , 23, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Jaswinder Singh
Feb 20, 2016

helium is a monoatomic gas so degree of freedom(f) = 3 C V = f R 2 C_{ V }=\frac { fR }{ 2 } C V = 3 R 2 C_{ V }=\frac { 3R }{ 2 } By mayor's formula C p = C V + R { C }_{ p }={ C }_{ V }+R Δ Q = n C p Δ T \Delta Q={ nC }_{ p }\Delta T Δ U = n C V Δ T \Delta U=n{ C }_{ V }\Delta T Δ U Δ Q = C V C P = 3 5 ∴ Δ U = 15 × 3 5 \frac { \Delta U }{ \Delta Q } =\frac { { C }_{ V } }{ { C }_{ P } } =\frac { 3 }{ 5 } \therefore \Delta U=15\times \frac { 3 }{ 5 } Δ W = Δ Q − Δ U = 15 − 9 = 6 k J \Delta W=\Delta Q-\Delta U=15-9=6kJ

3 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...