A classical mechanics problem by manish kumar singh

A pendulum bob has a speed of 3 m/s 3 \text{ m/s} while passing through its lowest position. What is its speed when it makes an angle of 60 degree with vertical?

Take the length of the pendulum to be 0.5 m 0.5 \text{ m} .
Take g = 10 m/s 2 g=10\text{ m/s}^2 .

1m/s 1.75m/s 2m/s 1.5m/s

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1 solution

Atvthe King
Aug 4, 2020

We use the property of conservation of mechanical energy.

v 2 + 2 g h v^2 + 2gh is a constant.

We see that as in the end we will have a different of heights, we can let h 0 = 0 h_0=0 The answer is then 9 2 10 ( 1 sin 30 ) = 4 \sqrt{9 - 2*10*(1-\sin30)} = 4

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