A classical mechanics problem by Naren Bhandari

If x x denotes displacement in time t t , and x = a cos t x = a \cos t where a a denotes any constant then acceleration will be ________ . \text{\_\_\_\_\_\_\_\_} .

a cos t -a \cos t a sin t -a \sin t a sin t a \sin t a cos t a \cos t

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1 solution

Tom Engelsman
Feb 1, 2017

If acceleration equals x ( t ) , x''(t), then x ( t ) = d 2 d t 2 [ a c o s ( t ) ] = a c o s ( t ) . x''(t) = \frac{d^{2}}{dt^{2}}[a \cdot cos(t)] = -a \cdot cos(t).

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