Rotational mechanics in an accelerated wedge

A 3 kg solid cylinder B of radius 2 metre and the 2 kg wedge A are held at rest at the position shown on an inclined plane of angle of inclination 30 degree.assuming the cylinder rolls without sliding on the wedge .Neglect friction between the wedge and ground.immediately after cord c has been cut,then

what is the acceleration(in m/s^2) of the wedge w.r.t earth?


The answer is 7.14.

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1 solution

Vijay Patel
Feb 25, 2018

Torque=I(alpha)....(1) fR=I(alpha)....(2)

Very useful....... Seriously ,very useful

Nishaanth Ramanathan - 2 years, 8 months ago

Idiotic fool noob

Bhavan loganatahn - 1 year, 7 months ago

Wow. Mind blowing answer 😒

Suriya Priyan - 7 months, 1 week ago

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