A Body of mass 10 kg is released from a point where it possesses an energy of 1920.8J .Find the velocity with which it hits the ground?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
By the Law of Conservation of Energy, we require:
P.E. = K.E.
if the gravitational potential energy is given to be 1920.8 J, then we have: 2 1 m v 2 = 1 9 2 0 . 8 ⇒ v = m 1 9 2 0 . 8 ⋅ 2 = 1 0 1 9 2 0 . 8 ⋅ 2 ≈ 1 9 . 6 m/s.