Parallel rays of light of intensity 912 watt per sq.m. a incidence on a spherical black body kept in surrounding of temp. 300 K take the stephen constant = 5.7*10^-8 watt per sq.m per K^-4 and energy exchange with the surrounding only through radiation the final steady state temp. of black body is closed to
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in steady state the total area at which light is incident is area of cross sectiomn of sphere ie 4Π r^2 energy incident per second = energy radiated per second
IΠr² = σ(t^4-t∘^4)4Πr²
I = σ(t^4-t∘^4)4
t^4-t∘^4 = 40×10^8
t^4 - 81×10^8 = 40×10^8
t^4 = 121×10^8
t = 330 k