A Clockwork Problem

Algebra Level 2

A clock is set at 10 o' clock and is perfectly functional. If the amount of time passed cannot be greater than an hour, what time will it be when the minute hand is in the same position the hour hand?

(Take note that the hour hand also moves every minute. Round down to the nearest minute.)

10:55 10:54 11:00 10:53

1 solution

Anthony Ling
Jul 26, 2014

x will equal to the number of minutes

$x = \frac{x}{12} + 50$

$\frac{11x}{12} = 50$

$11x=600$

$x=54.54$

54.54 minutes + 10 hours = 10:54.54, or 10:54

54.54 nearest minute is 55, not 54. ISO rule. Your solution is wrong and so is the problem solution

Humberto Bento - 6 years, 10 months ago

That is true, but what time is 10:54.54? It's still 10:54, and it's not yet 10:55. I also said clearly, in the italicized text, to round down to the nearest minute.

Anthony Ling - 6 years, 10 months ago

You are right, but it's somewhat misleading

Humberto Bento - 6 years, 10 months ago

A Clockwork Problem

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