A probability problem by A Former Brilliant Member

Probability Level pending

Of the two numbers, 4 times the smaller one is less than 3 times the larger one by 5. If the sum of the numbers is larger than 6 times their difference by 6. Find the sum of the digits of two numbers.

43 59 102 21

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1 solution

Let x and y are the two numbers.
x>y
Then, According To Question
●4y+5=3x...(1)
●(x+y)-6=6(x-y)...(2)
Solving (1) and (2) we get,
X=59 and Y=43
Adding all the digits,
5+9+4+3= 21 \boxed{21} .

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