A probability problem by Aniruddha Mandal
Probability
Level
1
Divide 282 into two parts such that the eighth part of the first and the fifth part of the second are in the ratio 4:3
56 & 97
60 & 70
192 & 90
79 & 98
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 solution
Let the two parts be and 282-x Therefore by the problem, 1/8x:1/5(282-x)=4:3 3x/32 * 5x/(282-x) 15x/32 282-32x 15x=32 282-32x 15x+32x=32 282 47x=32 282 Therefore, x=32*6 =»192 Therefore, (282-x)=282-192 =» 90