How do we separate it?

Find the number of ordered quadruples ( x 1 , x 2 , x 3 , x 4 ) ({ x }_{ 1 },\quad x_{ 2 },\quad { x }_{ 3 },\quad { x }_{ 4 }) of positive odd integers that satisfy i = 1 4 x i = 2016 \sum _{ i=1 }^{ 4 }{ { x }_{ i } } =2016


The answer is 170698584.

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1 solution

Otto Bretscher
Apr 2, 2016

If we write x i = 2 a i + 1 x_i=2a_i+1 , we need to count the non-negative integer solutions of a 1 + a 2 + a 3 + a 4 a_1+a_2+a_3+a_4 = 1006 =1006 . The answer is ( 1009 3 ) = 170698584 {1009 \choose 3}=\boxed{170698584}

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