A number theory problem by mridul jain

Someone observed that 6 ! = 8 9 10 6! = 8 \cdot 9 \cdot 10 . Find the largest positive integer n n^{}_{} for which n ! n^{}_{}! can be expressed as the product of n 3 n - 3_{}^{} consecutive positive integers.


The answer is 23.

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