Simple probability

Probability Level pending

If you take randomly one positive divisor or 8 and one positive divisor of 10.

What is the probability that their sum is greater than 8?

2 4 2^4 5 16 \frac5{16} 4 2 4^2 1 2 \frac12

Natanael Flores by Natanael Flores , 31, Mexico

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1 solution

Natanael Flores
Feb 19, 2016

The divisors of 8 are 1,2,4,8.

The divisors of 10 are 1,2,5,10.

We have 4*4=16 ways to sum one number of each group of divisors. (1+1,1+2,1+5,1+10,2+1,2+2,2+5..........)

There are only eight different sums greater than 8, 1+10, 2+10, 4+5, 4+10, 8+1, 8+2, 8+5 and 8+10.

So we have the probability 8 16 = 1 2 \frac{8}{16}=\frac{1}{2} .

1 Helpful 0 Interesting 0 Brilliant 0 Confused

Can you please reword the problem for clarity? It is kind of confusing and ambiguous.

Colin Carmody - 5 years, 3 months ago

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Done, I hope this time its understandable.

Natanael Flores - 5 years, 3 months ago

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