A probability problem by Rajdeep Bharati

Let n n be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls stand consecutively in the queue.

Let m m be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that exactly four girls stand consecutively in the queue.

Find the value of m n \dfrac mn .


The answer is 5.

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1 solution

Rajdeep Bharati
Feb 19, 2016

n = 6! × 5!

m = 6! × 5! × C(5, 4)

Therefore, m/n = 5

Your solution says that m/n = 5! = 120

Guillermo Templado - 4 years, 6 months ago

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No sir, my solution says that m/n = 4! x C(5,4) = 5

Rajdeep Bharati - 4 years, 6 months ago

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Please, dont call me sir, buddy, thank you anyway, but then 4! = 24 and C(5,4) =5 ,doesn't it? or what do you mean with C(5,4)?I don't understand you...

Guillermo Templado - 4 years, 6 months ago

I'm sorry. I have edited the solution.

Rajdeep Bharati - 4 years, 6 months ago

Can you elaborate, Sir ? Your 'm' specifically.

Vishal Yadav - 4 years, 3 months ago

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