A probability problem by Ricardo Luiz Motta

The independent term "c" of the equation x 2 3 x + c = 0 x ^ 2-3x + c = 0 is chosen randomly among elements { 1 , 0 , 1 , 2 , 3 } \{ -1,0,1,2,3 \} . What is the probability that the equation has real roots?


O termo independente "c" da equação x^2-3x+c=0.É escolhido aleatoriamente entre os elementos de {-1,0,1,2,3}.Qual é a probabilidade de essa equação vir a ter raízes reais?


The answer is 0.8.

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1 solution

Raghunathan N.
Oct 27, 2014

The equation has real roots if the discriminant of the equation is not negative.

By choosing -1, 0, 1, and 2 for c you find the discriminant is non-negative. i.e. real roots exist for 4 of the 5 values provided in the set.

Hence probability is 4/5 or 0.8

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