A Complex Square Root

Algebra Level 1

What is the imaginary part of − 169 \sqrt{-169} ?

Details and assumptions

If a complex number z z is equal to a + b i a + bi where a a and b b are real numbers and i 2 = − 1 i^2 = -1 is the imaginary unit, then the imaginary part of z z is b b (not b i bi ).


The answer is 13.

View wiki
Arron Kau by Arron Kau

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Arron Kau Staff
May 13, 2014

We have

− 169 = ( − 1 ) ⋅ 169 = 13 − 1 = 13 i = 0 + 13 i . \sqrt{-169} = \sqrt{(-1)\cdot 169} = 13 \sqrt{-1} = 13i = 0 + 13i.

Hence, the imaginary part is 13 13 and the real part is 0 0 .

3 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...