A composite function

Algebra Level 5

It is given that f ( x ) = x 3 3 x + 1 f(x) = x^3 - 3x + 1 . Find the number of real roots of f ( f ( x ) ) f(f(x)) .


The answer is 7.

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2 solutions

suppose f(x) has A , B ,C as its roots, then f(f(x))=0 when f(x) = A,B or C. So , draw the graph of f(x) and then draw lines of Y=A, Y=B , Y=C. These will intersect at 7 points!!!

Harsh Poonia
Jun 18, 2019

f ( x ) = x 3 3 x + 1 f(x)=x^3-3x+1 f ( x ) = 3 x 2 3 f'(x)=3x^2-3 f ( x ) = 0 at x = 1 , 1 f'(x)=0 \text{ at } x=1,-1 f ( 1 ) = 3 , f ( 1 ) = 1 f(-1)=3, f(1)=-1 For our final estimation, we see f ( 2 ) < 0 , f ( 2 ) > 0 f(-2) <0, f(2)>0 .

Thus the 3 roots of f ( x ) = 0 f(x)=0 are such that 2 < α < 1 -2< \alpha <-1 0 < β < 1 0< \beta <1 1 < γ < 2 1< \gamma < 2 Now estimate the graph of f ( x ) f(x) .

We could easily solve the problem without any rigorous calculation or actually solving the 9 degree resulting polynomial. Cheers!

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