A calculus problem by harshit kumar

Calculus Level 3

lim ⁡ x → 0 + e − 1 x = ? \Large \lim_{x \to 0^+} e^{-\frac 1x} = \ ?


The answer is 0.

Harshit Kumar by harshit kumar , 20, India

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2 solutions

x is not equal to 0. X approaches to 0, this is the meaning of limit: an aproximation in number conjunction x and f (x)

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Eriksone Lim
Oct 31, 2014

well I used the exponential rule in deriving it. the formula is d/dx[a^u]=(ln a) (a^u) u'= so it would be (ln e) (1/e^(1/x)) ((-1+x)/x^2) { quotient rule } then substituting x to 0, the whole equation will be 0.

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