A Cryptogram

Logic Level 2

A B C D = ( A D ) 2 \overline{ABCD}=\left(\overline{AD}\right)^2

If A , B , C A, B, C and D D are distinct non-zero digits, then find the value of A + B + C + D A+B+C+D .


The answer is 18.

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1 solution

Since the root gives D as unit and as square D can only be 1,5 or 6. Next to that A and the square of A have to give the same number. With some trial and error it is easily found that only 9 works. Thus leaves the choices 9 1 2 , 9 5 2 , 9 6 2 91^2, 95^2,96^2 . The last one is the only right fit, so the answer is 9 + 2 + 1 + 6 = 18 9+2+1+6=18 .

I agree with you

Andrea Virgillito - 4 years, 4 months ago

Can u please elaborate??

Prithwish Roy - 4 years, 3 months ago

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