A Delicious Problem

First, we need to name the expression which appears twice with a letter : "k"

5x² - 6x = k

After that, the main expression will become :

E(x) = E(k) = k(k + 3) + 2 = k² + 3k + 2

"What numbers have the sum equal to 3 and the product equal to 2 ?"

So, 3k is composed by 2k + 1k:

E(k) = k² + 2k + k + 2 = k(k + 2) + 1(k + 2) = (k + 2)(k + 1)

Now, we return to our main expression :

E(k) = E(x) = (5x² - 6x + 2)(5x² - 6x +1)

And the initial expression is a product of factors :

E(x) = (5x² - 6x + 2)(5x² - 6x +1)

Notice that the constant term of the expression $E(x)$ is 2, and only 1 of the given choices give you 2 for the constant term.