A Demonstration of Binomial Theorem

Algebra Level 3

The central term of ( 1 + x ) 2 n (1+x)^{2n} can be written as 1 3 5... ( 2 n 1 ) n ! 2 n x n \dfrac{1\cdot 3\cdot 5... (2n-1) }{ n! } \cdot { 2 }^{ n }\cdot { x }^{ n } ?

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1 solution

Consider the trivial case n=1. The solution is hence found.

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