A Diophantine equation

Are there infinitely many solutions to the equation m 2 5 n 2 = 1 \large m^{2}-5n^{2}=1 , where m and n are positive integers?

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1 solution

Freddie Hand
Feb 5, 2017

By trying out a few values, we find that m = 9 m=9 and n = 4 n=4 is a solution.

Now we can use induction.

If ( m , n ) (m,n) is a solution to m 2 5 n 2 = 1 m^{2}-5n^{2}=1 ,then ( m 2 5 n 2 ) 2 = 1 = ( m 2 + 5 n 2 ) 2 5 ( 2 m n ) 2 (m^{2}-5n^{2})^{2}=1=(m^{2}+5n^{2})^{2}-5(2mn)^{2} ,

Therefore, ( m 2 + 5 n 2 , ( 2 m n ) 2 ) (m^{2}+5n^{2},(2mn)^{2}) is also a solution. Therefore, there are infinitely many solutions to the equation m 2 5 n 2 = 1 m^{2}-5n^{2}=1 .

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