A probability problem by A Former Brilliant Member

Three different toys are to be given away to two girls and one boy (one toy per child). The children will be selected from four boys and six girls. In how many ways can this be done?


The answer is 360.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

n u m b e r o f w a y s = ( 4 C 1 ) ( 6 C 2 ) ( 3 ! ) = number~of~ways=(4C1)(6C2)(3!)= 360 \large{\color{plum}\boxed{360}}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...