A Dominating Problem
Solve in positive integers the equation:
Note : If think that there are infinitely many solutions or no solution, type .
The answer is 0.
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1 solution
We can rearrange the above equation as a^2=b^3-1.Then factoring b^3-1 as (b-1)(b^2+b+1)=a^2.Since for a number to be a square both the factor must equal ,we have b-1=(b^2+b+1),solving we get b=√-2 which is not a real number hence 'a' must also be a non real number.Therefore zero solution.