Electric Field Lines By Two Charges

It is said that $A$ and $B$ are $2$ electrically charged particles and the diagram illustrating the charges and their electric field is given. From, the diagram, we can see that the $A$ and $B$ are repelling each other as their electric field are not attracting but repelling each other. Now, we know that when 2 particles are having charges of the same sign -- either (+ve) or (-ve) , they repel each other. So, we can say that A and B have charges of same sign

Also, we see that the electric field lines of $A$ is more than that of $B$ , so we can say that The quantity of electric charge of A is larger than that of B .

Now, electric field intensity at $P$ is observed to be greater than that at $Q$ in the diagram, so we can say that Electric field strength at P is stronger than that at Q .

But, from the diagram, we see that the field lines are generating and propagating in outward direction from the particles, so they $(A\text{ and }B)$ are (+ve)ly charged and placing a (+ve) charge at P would make the placed charge and $B$ repel from each other not get dragged to each other. So, we see that This explanation is incorrect .

So, the incorrect explanation is D.

The value of charge at point B is +ve because the electic field lines are towards outwards.Hence placing a +ve charge at P will make it to repel from that at B.Hence it will not get dragged to B.