A equation involving prime.

Find sum of all positive integers m m , n n and primes p 5 p≥5 such that

m ( 4 m 2 + m + 12 ) = 3 ( p n 1 ) m(4m^{2}+m+12)=3(p^{n}-1) .

For example, if the solutions are ( 1 , 2 , 5 ) (1,2,5) and ( 3 , 2 , 7 ) (3,2,7) then the answer will be

1 + 2 + 5 + 3 + 2 + 7 = 20 1+2+5+3+2+7=20

This is a INMO problem.


The answer is 23.

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1 solution

f 1 = m ( 4 m 2 + m + 12 ) 3 ( p n 1 ) m x , 1 , 50 p n I l e t p v a r y f r o m 5 , 7 , 11 , 13 , 17 a n d n = 1 t o 7. x w a s a d j u s t e d s o i n t h e l i s t f o r f t h e r e w e r e b o t h + t i v e a n d t i v e v a l u e s . E x c e p t f o r ( 12 , 4 , 7 ) , f j u m p e d f r o m + t i v e t o t i v e v a l u e s . B e l o w t h e r e l e v a n t o b s e r v a t i o n s ( m , n , p ) . . . . . . . . . . f m = . . . . . . + t i v e ( m + 1 , n , p ) . . . . . f m + 1 = . . . . t i v e ( 1 , 1 , 7 ) . . . . . f 1 = 1 , ( 2 , 2 , 7 ) . . . . . f 2 = 84 , ( 6 , 3 , 7 ) . . . . . f 6 = 54 ( 2 , 1 , 7 ) . . . . . f 2 = 42 , ( 3 , 2 , 7 ) . . . . . f 3 = 9 , ( 7 , 3 , 7 ) . . . . . f 7 = 479 , ( 11 , 4 , 7 ) . . . . . f 11 = 1623 ( 12 , 4 , 7 ) . . . . . f 12 = 0 , ( 13 , 4 , 7 ) . . . . . f 13 = 1913 , ( 23 , 5 , 7 ) . . . . . f 23 = 945 , ( 1 , 1 , 11 ) . . . . . f 1 = 13 , ( 9 , 3 , 11 ) . . . . . f 9 = 885 , e c t . ( 24 , 5 , 7 ) . . . . . f 24 = 5742 , ( 2 , 1 , 11 ) . . . . . f 2 = 30 , ( 10 , 3 , 11 ) . . . . . f 10 = 230 , e c t . B e l o w i s t h r o u g h g r a p h . S w e e p i n g a n d c h e c k i n g b y m a g n i f y i n g t o s e e w h e r e x = w i s a n i n t e g e r . \color{#3D99F6}{f_1=m(4m^2+m+12)-3(p^n-1)\\ m|x,1,50 \\ p\\ n}\\ ~~~ \\ I ~let~p~vary~from~5,7,11,13,17\\ and~n=1~to~7.\\ x~was~adjusted~so~in~the~ list ~for~f~~there~were~both~+tive~and~-tive~values.\\ Except~for~(12,4,7), ~f~jumped~from~+tive~to~-tive~values.\\ Below~the~ relevant~observations\\ (m,n,p)..........f_m=......+tive\\ (m+1,n,p).....f_{m+1}=....-tive\\ (1,1,7).....f_{1}=1,~~~~~~(2,2,7).....f_{2}=84,~~~~~(6,3,7).....f_{6}=54\\ (2,1,7).....f_{2}=-42,~~~~~(3,2,7).....f_{3}=-9,~~~~~(7,3,7).....f_{7}=-479,\\ (11,4,7).....f_{11}=1623~~~~~~~~~~~~\\ \color{#BA33D6}{(12,4,7).....f_{12}=0,}~~~~\\ (13,4,7).....f_{13}=-1913,~~~~\\ (23,5,7).....f_{23}=945,~~~~~~~(1,1,11).....f_{1}=13,~~~~~(9,3,11).....f_{9}=885,~~~~~ect.\\ (24,5,7).....f_{24}=-5742,~~~~~(2,1,11).....f_{2}=-30,~~~~~(10,3,11).....f_{10}=-230,~~~~~ect.\\ ~~~~~~\\ Below~is~through~graph.~ Sweeping~and~checking~by~magnifying~to~see~where~x=w~is~an~integer.

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