If I pick a number at random among the first 1000 Fibonacci numbers, what's the probability that it will be even?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
1 , 1 , 2 , 3 , 5 , 8 , 1 3 , 2 1 , 3 4 , 5 5 . . .
The pattern keeps going on,so among three consecutive Fibonacci numbers,there are always one even and two odds.