A Fight of Kings!

In how many ways can a white and a black king be placed on a 8 × 8 8 \times 8 chessboard without any of the two threatening each other?

Image credit: Dp Challenge heydandy


The answer is 3612.

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1 solution

Arpit MIshra
Apr 21, 2015

The white king can be placed on any square among the 64 squares. However the areas it attacks depends on its position.

Case I: If the white king is placed on any other square excluding the edges of the chessboard it attacks 9 squares including the square on which it is placed. Therefore it leaves 64-9 = 55 squares safe. Since there are 64-28 = 36 such squares, therefore there are:

55 × 36 55 \times 36 = 1980 1980 combinations.

Case II: If the white king is placed on the edge of the chessboard (excluding corners) it attacks 6 squares including the square on which it is placed. Therefore it leaves 64-6 = 58 squares safe. Since there are twenty-four such squares of this type, therefore there are:

58 × 24 58 \times 24 = 1392 1392 combinations

Case III : If the white king is placed on any of the four corners of the chessboard it attacks 4 squares including the square on which it is placed. Therefore it leaves 64-4 = 60 squares safe, therefore there are:

60 × 4 60 \times 4 = 240 240 combinations.

Therefore there are: 1980 + 1392 + 240 1980 + 1392 + 240 = 3612 \boxed{3612} squares where the two kings do not threaten each other.

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