A Fisheries Problem

Calculus Level 4

A fish farmer wants to use a pond for his fishing. He finds that the pond has a capacity of M M fish.

He also finds that population growth rate is proportional to the product of 'the number of fish in the pond' and 'the additional number of fish which can be accommodated in the pond'; with a proportionality constant α \alpha .

If the optimal rate of harvest is R R , what is the value of 1000 R π α M 2 \left\lfloor\frac{1000R\pi}{\alpha M^2}\right\rfloor


The answer is 785.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Murali Kancharla
Feb 20, 2015

R=ax(m/2)x(m/2), at x=m/2. value is 1000*3.14/4=785

Find the number of fish at any point of t ?

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...