A for Apples and B for Bananas

Let a=apple and b=banana

so we have,

2a + 3b = $3.05

3a + 2b = $3.20

Solving this equation, we have,

a = 0.7 & b = 0.55

Hence, (0.7x7) + (0.55x7) = $8.75

$10 - $8.75 = $1.25 _ _ _ (Change received)

suppose, $\text{ banana=B and apple=A}$

so, $2A+3B=305$ ..............[converting them to cents]

and, $3A+2B=320$

so, $5A+5B=320+305$ .........[adding these two]

or, $A+B=\frac{625}{5}$

or, $7A+7B=\frac{625 \times 7}{5}$ = $875$ = $8.75$ $

so, the change will be= $10-8.75=1.25$ $

Let x be apples and y be bananas.

As what the problem stated...

2x + 3y = 3.05 and 3x + 2y = 3.20

"Combine" the two equations. (2x + 3x = 5x) (3y + 2y = 5y) (3.05 + 3.20 = 6.25)

5x + 5y = 6.25

$\frac{5x + 5y}{5}$ = $\frac{6.25}{5}$

Cancel the 5's on the left side.

x + y = 1.25

It says, "7 of both fruits". Lets try...

7x + 7y = 7(1.25)

           = 8.75

And the thing that is asked, "How much change will you get from a 10-dollar bill?"

10 - 8.75 = change

             = $1.25

Therefore, $1.25 is the change. (Sorry for the wrong expressions!)

$\begin{aligned} 2a+3b&=3.05 \\ 3a+2b&=3.20 \\ \implies 5a+5b&=6.25 \\ \implies a+b&=1.25 \\ \implies 7a+7b&=8.75 \\ 10-8.75&=\boxed{1.25} \end{aligned}$

Hello,

as for an apple = a , banana = b,

2a + 3b = 3.05

3a + 2b = 3.20

By using an elimination method,i wanna to get rid of a,

3(2a + 3b) = 3.05(3)

6a + 9b = 9.15

2(3a + 2b ) = 3.20(2)

6a + 4b = 6.4

so by elimination of ,

6a + 9b = 9.15 (1st)

6a + 4b = 6.4 (2nd)

(1st) - (2nd),

5b = 9.15 - 6.4

b = 0.55

2a = 3.05 - (3 x 0.55) = 1.4

a = 0.7

therefore if i bought 7 apples and 7 bananas by using $ 10,

remainder = $10 - [ ( 7 x 0.7) + ( 7 x 0.55 ) ] = $ 1.25

thanks...