A geometry problem by Ankit Nigam
Geometry
Level
pending
If P(1,2), Q(4,6), R(5,7), S(a,b) are the vertices of parellelogram PQRS, then
PRACTICE FOR BITSAT HERE
a=3, b=4
a=2, b=3
a=2, b=4
a=3,b=0
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1 solution
E q u a t i n g s l o p e o f P Q a n d R S , a − 5 b − 7 = 3 4 ∴ 4 a − 3 b = − 1 − − − − − ( 1 )
E q u a t i n g s l o p e o f P S a n d R Q , a − 1 b − 2 = 1 1 ∴ a − b = − 1 − − − − − ( 2 )
∴ a = 2 a n d b = 3