A geometry problem by Anthony Pham

Geometry Level 4

Observe net A B C D E F G H I J ABCDEFGHIJ .

Figure B E G J BEGJ is a unit square, with angle A B J = 9 0 ABJ=90^\circ and B J = A B = B C BJ=AB=BC . Also, D E = E F = F G = G H DE=EF=FG=GH and C E = A J = J I CE=AJ=JI , with the ratio of G H GH to I J IJ is 1 : 2 1:2 . The net is to form a closed polyhedron no holes or overlaps. If the volume is written as a fraction in lowest terms, find the sum of the numerator and the denominator.


The answer is 17.

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1 solution

Bob Kadylo
Sep 7, 2018

The closed polyhedron has 6 vertices in 3D space: A,C,I come together at (0,0,1), B is (0,0,0), E is (0,-1,0), G is (1,-1,0), J is (1,0,0) and D,F,H come together at (.5,-1,.5). I then sliced the solid with a plane through points A, E and G. The part with a square base had area 1 and volume 1 3 \frac{1}{3} .

The part with a triangle base AEG and apex F had a volume of 1 12 \frac{1}{12} . Total volume is 5 12 \frac{5}{12} . Answer is 17 \boxed{17}

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