The figure above two similar semicircles of radius inscribed inside a rectangle.
Let the area of the green region and blue region be denoted by and , respectively.
If the vaue of (A1-A2)/A1 equals , where are all integers with square-free, find .
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From the figure , by using some geometrical concepts we will get the length of the chord GH = √3.R Area of the circular Segment GHN = ( θ/360 × π − sin(θ)2)× R2 , so far , A1/2 = R²(π/3 - √3/4) , A1 = 2R²(π/3 - √3/4) then, Also the Area of the circular segment ABGH = πR²/2 – A1/2= R²(π/2 - π/3 + √3/4 ) . ABGH = R²(π/6 + √3/4 ) . Now , A2/2 = R² - R²(π/6+√3/4) = R²(-π/6-√3/4+1). then, 2R²(-π/6-√3/4+1) = A2 .
from previous results A1-A2 = 2R²(π/2-1) . A1 = 2R²(π/3-√3/4). Hence : (A1-A2)/A1 = (π/2-1)/ (π/3-√3/4) = (6π-12)/(4π-3√3) Therefore, a+b+c+d = 6+12+4+3= 25 .