A geometry problem by Charuka Bandara

$E$ and $N$ are points on the sides $DC$ and $DA$ of the square $ABCD$ such that $AN : ND : DE = 2 : 3 : 4.$ The line through $N$ perpendicular to $BE$ cuts $BE$ at $P$ and $BC$ at $M$ . $AC$ cuts $MN$ at $O$ and $BE$ at point $S$ . What fraction of the area of $ABCD$ is the area of triangle $OPS$ ?

Give your answer to the first decimal place.