The figure above shows an incircle of a triangle A B C with sides 6-12-17. Let P and Q be the points on the side lengths A B and A C respectively, such that P Q is tangent to the incircle. Find the perimeter of the triangle A P Q .
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Very nice solution! (+1)
P B C Q is a tangent quadrilateral so P B + Q C = P Q + B C ( 1 ) . Wanted perimeter is O = P Q + A P + A Q . Next P B = A B − A P and Q C = A C − A Q . If we put that in ( 1 ) we get:
A B − A P + A C − A Q = P Q + B C ⟹ A B + A C − B C = P Q + A P + A Q ⟹ 1 7 + 6 − 1 2 = O Thus O = 1 1 .
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