Find the value of x in term a , b , and c .
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Our Original Figure is B A C D E F . Where ∠ B A C = x , ∠ A C D = a , ∠ C D E = b and ∠ D E F = c
Join Point C and Point F . From the Figure :
∠ B A C = ∠ C F E = x and ∠ D C F = 1 8 0 − a
In Quadrilateral C D E F :
x + 1 8 0 − a + b + c = 3 6 0
x = a − b − c + 1 8 0
Doesn't this solution assume that lines AB and EF are parallel? Nothing about the problem suggests this is the case. Or am I missing something?
@Sambhrant Sachan Nice solution
@Sambhrant Sachan Can you rate this problem?
@Jose Chavira The two arrows indicate that the lines are parallel
This is the solution I picked before submitting the answer.
@Sambhrant Sachan Thank you
7 2 0 = x + ( 3 6 0 − a ) + b + c + 9 0 + 9 0
7 2 0 = x + 5 4 0 − a + b + c
1 8 0 + a − b − c = x
amazing that is the best method to apprehend this problem.
very simple solution from the figure :
since in the figure we have a quadrilateral and because sum of angles of quadrilateral is 3 6 0
= > x + b + c + 1 8 0 − a = 3 6 0 = = > x = 1 8 0 + a − b − c
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b − ( 1 8 0 − c ) = a − x
x = a − b − c + 1 8 0