Zig Zag Lines And Their Relationships

Geometry Level 2

Find the value of x x in term a , b , a, b, and c c .

a + b + c 180 a+b+c-180 a b + c + 180 a-b+c+180 a + b c + 180 a+b-c+180 a b c + 180 a-b-c+180

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6 solutions

Fidel Simanjuntak
Jul 19, 2016

b ( 180 c ) = a x b-(180-c) = a-x

x = a b c + 180 x=a-b-c+180

Sabhrant Sachan
Jul 19, 2016

Our Original Figure is B A C D E F BACDEF . Where B A C = x \angle BAC = x , A C D = a \angle ACD = a , C D E = b \angle CDE = b and D E F = c \angle DEF = c

Join Point C C and Point F F . From the Figure :

B A C = C F E = x \angle BAC = \angle CFE = x and D C F = 180 a \angle DCF = 180-a

In Quadrilateral C D E F CDEF :

x + 180 a + b + c = 360 x+180-a+b+c=360

x = a b c + 180 \boxed{x=a-b-c+180}

Doesn't this solution assume that lines AB and EF are parallel? Nothing about the problem suggests this is the case. Or am I missing something?

Jose Chavira - 4 years, 9 months ago

@Sambhrant Sachan Nice solution

Fidel Simanjuntak - 4 years, 11 months ago

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Your solution is much better :)

Sabhrant Sachan - 4 years, 11 months ago

@Sambhrant Sachan Can you rate this problem?

Fidel Simanjuntak - 4 years, 11 months ago

@Jose Chavira The two arrows indicate that the lines are parallel

Eric Kim - 4 years, 6 months ago

This is the solution I picked before submitting the answer.

Avery Bentley Sollmann - 4 years, 4 months ago

@Sambhrant Sachan Thank you

Fidel Simanjuntak - 4 years, 11 months ago

720 = x + ( 360 a ) + b + c + 90 + 90 720 = x + (360 - a) + b + c + 90 + 90

720 = x + 540 a + b + c 720 = x + 540 - a + b + c

180 + a b c = x 180 + a - b - c = x

amazing that is the best method to apprehend this problem.

Ali Jafri - 3 years, 11 months ago
Syed Hissaan
Feb 2, 2017

very simple solution from the figure :

since in the figure we have a quadrilateral and because sum of angles of quadrilateral is 360 360

= > x + b + c + 180 a = 360 = = > x = 180 + a b c => x + b + c + 180 -a =360 ==>x=180 +a -b -c

Omar Monteagudo
Jan 18, 2017

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