A geometry problem by Guntitat Sawadwuthikul

Geometry Level 3

ABC is a right triangle, with the length of x , y x, y and z z , with z z represents the hypotenuse. If the height of the triangle equals to 8, having z z as the base. Find the value of ( x + 8 ) ( y + 8 ) ( x 8 ) ( y 8 ) (x+8)(y+8)(x-8)(y-8) .


The answer is 4096.

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2 solutions

As Δ A B C \Delta ABC is right angled we know that x 2 + y 2 = z 2 x^{2} + y^{2} = z^{2} and x y = 8 z xy = 8z . So

( x + 8 ) ( y + 8 ) ( x 8 ) ( y 8 ) = ( x 2 64 ) ( y 2 64 ) = (x + 8)(y + 8)(x - 8)(y - 8) = (x^{2} - 64)(y^{2} - 64) =

( x y ) 2 64 ( x 2 + y 2 ) + 6 4 2 = ( 8 z ) 2 64 z 2 + 4096 = 4096 (xy)^{2} - 64(x^{2} + y^{2}) + 64^{2} = (8z)^{2} - 64z^{2} + 4096 = \boxed{4096} .

Ahmad Saad
Dec 16, 2016

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