A geometry problem by harpreet singh
Geometry
Level
3
ABC is an acute angled triangle and CD is the altitude through C. If AB = 80 and CD = 60, find the distance MN, where M and N are mid points of AD and BC respectively.
The answer is 50.
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I solved it with complete symbolic forms and then I deduce every thing in the triangles and it's segments So we can solve these equations and find that MN=1/2. Sqrt(AB^2+CD^2)