A right triangle is divided into six smaller triangles by lines drawn from the vertices through a common interior point named as .
These lines which are drawn from vertices meet at points , respectively.
The areas of triangles are 84,35,30 and 40, respectively.
What is the area of triangle ?
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We will use the fact that for triangles with the same height (or base), the ratio of their areas is the ratio of their base (or height).
first ratio: [ B O F ] [ A O F ] = B F A F = [ B C F ] [ A C F ]
y 8 4 = y + 4 0 + 3 0 8 4 + x + 3 5
y 8 4 = y + 7 0 1 1 9 + x (this is our equation 1)
second ratio: [ C O E ] [ A O E ] = C E A E = C B E ] [ A B E ]
3 5 x = 4 0 + 3 0 + 3 5 x + y + 8 4 ⇒ 3 5 x = 1 0 5 x + y + 8 4
x = 0 . 5 y + 4 2 (this is our equation 2)
Solving the system of equations by substituting equation 2 into equation 1,
y 8 4 = y + 7 0 1 1 9 + 0 . 5 y + 4 2
0 . 5 y 2 + 7 7 y − 5 8 8 0 = 0
y = 5 6
x = 0 . 5 y + 4 2 = 7 0
Thus, the total area is 8 4 + 5 6 + 7 0 + 4 0 + 3 0 + 3 5 = 3 1 5