A geometry problem by HoangGia Pham

Geometry Level pending

From My Triangle Geometry

Area of Orthic Triangle HaHbHc is orthic triangle of triangle ABC. A', B', C' are orthogonal projections of A, B, C on HbHc, HcHa, HaHb respectively. Please prove that: Area(HaHbHc) = Sqrt(Area(ABC)*Area(A'B'C'))

S(HaHbHc)=2√3S(ABC)*S(A'B'C') S(HaHbHc)= √2S(ABC)*S(A'B'C') S(HaHbHc)=1/4S(ABC)*S(A'B'C') S(HaHbHc)=1/8

HoangGia Pham by HoangGia Pham , 20, Vietnam

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