A geometry problem by Jason Hicks
A house sits on a lot 92 feet wide and 112 feet deep. The house is 42 feet long and 26 feet wide. There are 3 gardens, one is 4 feet round, another is 8.5 feet wide by 12 feet long, and the last garden is 12.5 feet wide and 21 feet long. There are two side walks. The first runs the width of the lot and is four feet wide, and the other runs to the front door and is 2 feet wide and 12 feet long. Assuming the remaining area is grass what is the square footage? (Round to the nearest integer)
The answer is 8443.
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